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PHP+JS三级菜单联动菜单实现方法

更新时间:2020-03-07 23:55:18 作者:startmvc
本文实例讲述了PHP+JS三级菜单联动菜单实现方法。分享给大家供大家参考,具体如下:<ht

本文实例讲述了PHP+JS三级菜单联动菜单实现方法。分享给大家供大家参考,具体如下:


<html>
 <head>
 <title>
 智能递归菜单-读取数据库
 </title>
 <style>
 TD { FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; LINE-HEIGHT: 130%;
 letter-spacing:1px } A:link { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体";
 FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:visited
 { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
 none; letter-spacing:1px } A:active { COLOR: #990000; FONT-FAMILY: "Verdana",
 "宋体"; FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:hover
 { COLOR: #ff0000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
 underline; letter-spacing:1px } .Menu { COLOR:#000000; FONT-FAMILY: "Verdana",
 "宋体"; FONT-SIZE: 12px; CURSOR: hand }
 </style>
 <script language=javascript>
 function ShowMenu(MenuID) {
 if (MenuID.style.display == "none") {
 MenuID.style.display = "";
 } else {
 MenuID.style.display = "none";
 }
 }
 </script>
 </head>
 <body>
<?php
// $Id:$
//基本变量设置
$GLOBALS["ID"] = 1;
//用来跟踪下拉菜单的ID号 $layer=1;
//用来跟踪当前菜单的级数
//连接数据库
$Con=mysql_connect( "localhost", "root", "123456"); mysql_select_db(
"menu");
//提取一级菜单
$sql="select * from menu where parent_id=0" ;
$result=mysql_query($sql,$Con);
//如果一级菜单存在则开始菜单的显示
if(mysql_num_rows($result)>0) ShowTreeMenu($Con, $result, $layer, $ID); 
//=============================================
//显示树型菜单函数 ShowTreeMenu($con,$result,$layer) //$con:数据库连接 
//$result:需要显示的菜单记录集
//layer:需要显示的菜单的级数 
//=============================================
function
ShowTreeMenu($Con, $result, $layer) {
//取得需要显示的菜单的项目数
$numrows=mysql_num_rows($result);
 //开始显示菜单,每个子菜单都用一个表格来表示 echo "
 < tablecellpadding = '0'cellspacing = '0'border = '0' > "; for($rows=0;$rows
 <$numrows;$rows++) { //将当前菜单项目的内容导入数组 $menu=mysql_fetch_array($result);
 //提取菜单项目的子菜单记录集 $sql="select * frommenuwhereparent_id = $menu[id]" ; $result_sub=mysql_query($sql,$Con);
 echo " < tr > "; //如果该菜单项目有子菜单,则添加JavaScript onClick语句 if(mysql_num_rows($result_sub)>
 0) { echo " < tdwidth = '20' > < imgsrc = 'tree_expand.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu'onClick = 'javascript:ShowMenu(Menu".$GLOBALS["ID"].");' > "; } else { echo " < tdwidth = '20' > < imgsrc = 'tree_collapse.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu' > "; } //如果该菜单项目没有子菜单,并指定了超级连接地址,则指定为超级连接, //否则只显示菜单名称 if($menu[url]!="")
 echo " < ahref = '$menu[url]' > $menu[name] < / a > "; else echo $menu[name]; echo " < / td > < / tr > "; //如果该菜单项目有子菜单,则显示子菜单 if(mysql_num_rows($result_sub)>0) { //指定该子菜单的ID和style,以便和onClick语句相对应
 echo " < trid = Menu".$GLOBALS["ID "]++ . " style='display:none'>";
 echo "<td width='20'></td>";
 echo "<td>";
 //将级数加1
 $layer++;
 //递归调用ShowTreeMenu()函数,生成子菜单 
 ShowTreeMenu($Con,$result_sub,$layer);
 //子菜单处理完成,返回到递归的上一层,将级数减1
 $layer--;
 echo "< / td > < / tr > ";
 }
 //继续显示下一个菜单项目
 } echo " < / table > "; }
 ?>
 <?php
 $id=1 ;
 function test() {
 global $id; unset($id);
 }
 test();
 echo " < fontclass = menu > ".($id). " < / font > ";
 // 在 PHP 4 中这里会打印出 1
 ?>
 <?php
 $a=1 ;
 $b=2 ;
 function Sum() {
 global $a, $b; $b=$ a + $b;
 }
 Sum();
 echo " < fontclass = menu > ".$b. " < / font > ";
 ?>
 </body>
</html>

PHP JS 三级菜单 联动菜单